# Speed Calculations

## Calculations: Overview

## Calculations: Background

Think of the zip line as a catenary curve shown in Figure 2. The catenary curve is the natural shape that a cable assumes hanging under its own weight when supported at the two ends. The cable of the zip line approximates a skewed catenary curve because of the different heights of the end points. When the rider's weight is applied to the cable, the shape of the cable will change as the rider's weight pulls the cable into a "straight line." The shape of the catenary curve now resembles more closely the lines of a triangle where the angles and side lengths reflect cable tension and the change in the rider's position.

The equations needed to calculate a rider’s theoretical maximum speed are derived from the Pythagorean Theorem, Newton’s Second Law of Motion, and a Kinematic Equation that relates displacement, velocity, and acceleration.

The Pythagorean Theorem relates the three sides of any right triangle – a triangle in which one angle is 90 degrees. The theorem states that

${a}^{2}+{b}^{2}={c}^{2}$*${a}^{2}+{b}^{2}={c}^{2}$*

Newton’s Second Law of Motion states that the force of an object is equal to its mass multiplied by its acceleration. This verbal statement is often expressed in equation form as:

*$F=m\times a$*

Kinematic Equations are a set of scientifically accepted equations for finding unknown information about an object’s motion when other information is known. The equations can be used for any motion that can be classified as either constant velocity or constant acceleration. The equation needed to find maximum velocity is as follows:

*${V}_{f}^{2}={V}_{i}^{2}+2\times a\times d$*

Where:

${V}_{i}$is initial velocity

a is acceleration

d is displacemen

Upon stepping off the platform Newton's Laws of Motion become evident. The absence
of the platform provides the unbalanced force that sets the rider in motion. The
rider drops, gravity takes over, and you begin to accelerate. This illustrates
the 2
^{nd} Law. The rider is no longer at rest and continues along the zip line until
a braking force is applied.

## Calculations: Procedure

### Step 1: Determine the Distance Traveled

The distance traveled (the hypotenuse of the right triangle) is approximated using the Pythagorean Theorem.

*$\mathrm{Distance}\left(d\right)=\sqrt{\mathrm{horizontal}{\mathrm{distance}}^{2}+\mathrm{vertical}{\mathrm{drop}}^{2}}$*

### Step 2: Approximate Acceleration

We know that acceleration reflects Newton's Second Law of Motion (F = ma). Since there are multiple forces acting on the rider, the symbol epsilon 'Σ' must be used to represent the sum, or net, of these forces. Thus,

In reality, there are two primary forces that affect acceleration; one is due to the component of gravity in the direction of motion and the other is a combination of friction and other resistive forces (collectively called 'loss').

On a zip line, friction and the other resistive forces are difficult to calculate. However, since these resistive forces have a significant impact on the calculated results (potentially causing up to a 1/3 reduction in maximum speed), they cannot be ignored. The best method for quantifying loss is through scientific experimentation.

Gravity acting on the rider's mass produces the dominant force. Consider the rider moving across the zip line as a variation of the classical block sliding down an inclined plane problem that is introduced in many entry level physics courses. We can apply the sine function of the cable slope angle (θ) to calculate the force due to gravity in the direction of motion. This can be better understood by observing Figure 4.

Thus, the force due to gravity in the direction of motion is determined by multiplying the rider's mass

**(m)**by gravitational acceleration

**(g)**by the

**sin (θ)**.

The original equation now becomes:

*$\mathrm{Acceleration}\left(a\right)=\frac{\Sigma \mathrm{Forces}}{\mathrm{mass}}=\frac{m\times g\times \mathrm{sin}\left(\theta \right)-\mathrm{loss}}{m}$*

Where:

m = mass,

g = gravitational acceleration

θ = cable slope angle

Since the mass term in each part of the equation cancels, the equation simplifies to:

*$\mathrm{Acceleration}\left(a\right)=g\times \mathrm{sin}\left(\theta \right)-\mathrm{loss}$*

### Step 3: Calculate Maximum Velocity

The maximum velocity can be determined using a kinematic equation:

*$\mathrm{Maximum}{\mathrm{velocity}}^{2}\left({{V}_{max}}^{2}\right)=\mathrm{initial}{\mathrm{velocity}}^{2}+a\times d$*

Where:

a = acceleration

d = distance traveled

Since the initial velocity is assumed to be zero, this equation simplifies to:

*$\mathrm{Maximum}\mathrm{Velocity}\left(V\mathrm{max}\right)=\sqrt{2\times a\times d}$*